p-chain
A p-chain (for ), of is a formal sum of the -simplices in
where are coefficients in some underlying group .
Typically the underlying group is or .
One may think of -chains as vectors with elements in . In fact, we can easily construct a group by defining the operation to be as we expect:
Under this operation we get , the group of -chains of . For a simplicial complex , there always exists for . For or , we define to be the trivial group.
When a simplicial complex has finitely many simplices , the -chains group is finitely generated by the elementary p-chains where
Boundary Map
We can connect chain groups with the boundary map .
Boundary
The boundary of a -simplex is the -chain formed by taking the sum of all -faces, i.e., if , then
where denote an omitted vertex.
Note that when working over , for all . So the boundary becomes
Thus, given a -chain , the p-th boundary map is defined by
One may verify that is in fact a homomorphism, that is, .
Since is defined for , we get a chain (called a chain complex) of boundary homomorphisms:
Note that the chain complex forms an abstract simplicial complex.
Cycles and Boundaries
p-cycle
A p-cycle is a -chain with empty boundary, i.e., .
The set of -cycles, , is a subgroup of . More specifically,
Typically, is a proper subgroup of , however for any 0-simplex , . Thus, when we get that .
p-boundary
A p-boundary is a -chain that is the boundary of some -chain, i.e., for some .
The set of -boundaries, is a subgroup of . More specifically,
In fact, is actually a subgroup of due to the fundamental law of homology:
Fundamental Law of Homology
for all
Therefore, our chain complex
is exact, i.e., .
Homology Groups
Homology Group
The p-th homology group is the quotient group
and is composed of classes of cycles that are not boundaries.
Each element of is given by adding -boundaries to a given -cycle: . Another is in the same class as if . In such a case, and are called homologous which is denoted .
The operation in is the typical quotient group operation:
Therefore, is abelian as our underlying group is either or .